Find the second largest number in an unsorted array without any built-in method in JavaScript

<script>    let array = [10, 30, 35, 20, 30, 25, 90, 89];    function secondLargestNumber(array) {        let max = 0;        let secondMax = 0;        for (let i = 0; i < array.length; i++) {            if (array[i] > max) {                max = array[i];            }        }        for (let i = 0; i < array.length; i++) {            if (array[i] > secondMax && array[i] !== max) {                secondMax = array[i];            }        }        return secondMax;    }    console.log(secondLargestNumber(array));</script>