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Select unique elements from an Array using: lastIndexOf() & indexOf()
Hello guys! So, today I am going to show you how to use the following built-in array methods (lastIndexOf() & indexOf()) to select unique elements from an array.
indexOf()
The indexOf() method of the array returns the first index or position at which a given element can be found in the array. It returns -1 if the element is not found.
Eg:
const numberArray = [1,2,3,4];const index = numberArray.indexOf(3);console.log(index) => 2const noIndex = numberArray.indexOf(9);console.log(noIndex) => -1
lastIndexOf()
The lastIndexOf() method of the array returns the last index or position at which an element can be found in an array. The array is searched backwards.
Eg:
const numberArray = [1,2,3,4,5,7,3,6,9];const lastIndex = numberArray.lastIndexOf(3);console.log(lastIndex ) => 6const noLastIndex = numberArray.lastIndexOf(90);console.log(noLastIndex ) => -1
Now, let's go into the business of the day.
NOTE: The purpose of this tutorial is not to make an array of repeated values a unique array, rather it is to pick elements that appear only once in a repeated array.
Example
Given an array of repeated values:
const repeatedVals = [5, 7, 3, 9, 4, 9, 8, 3, 2, 7, 2];
We are going to output a new array of unique values.
function uniqueValues(arr) { const uniqueVals = []; return uniqueVals}
Explanation: we created a function, inside the function, we created an empty array to hold the unique values and then return that new array. Next, we are going to write our for-loop and some conditions.
// [5, 7, 3, 9, 4, 9, 8, 3, 2, 7, 2];function uniqueValues(arr) { const uniqueVals = []; const lenOfArr = arr.length; for (let i = 0; i < lenOfArr; i++){ const val = arr[i]; if (arr.lastIndexOf(val) === arr.indexOf(val)) { uniqueVals.push(val) } } return uniqueVals}uniqueValues(repeatedVals)
Output-
[5, 4, 8]
Explanation:
The if
conditional simply checks if the returned indices of both methods are equal. In the case where they are not equal, it simply means that the current value has a duplicate in the array.
Thank you for checking out this post. In case of any errors or suggestions, kindly notify me.
Original Link: https://dev.to/felistus/select-unique-elements-from-a-array-using-lastindexof-indexof-5dnh
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